0=1x^2+10x+9

Solution for 0=1x^2+10x+9 equation:

0=1x^2+10x+9

We move all terms to the left:

0-(1x^2+10x+9)=0

We add all the numbers together, and all the variables

-(1x^2+10x+9)=0

We get rid of parentheses

-1x^2-10x-9=0

a = -1; b = -10; c = -9;
Δ = b2-4ac
Δ = -102-4·(-1)·(-9)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-8}{2*-1}=\frac{2}{-2}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+8}{2*-1}=\frac{18}{-2}
=-9
$